Practice Set 1 – Animated Solutions ചിന്തിക്കാം
The textbook asks you to solve these eight puzzles mentally, with one letter, or with two equations – whichever you like. For each one, read the question, try it in your notebook (use the hint if you are stuck), then press Next ▶ and watch the solution grow.
- Set the extra aside: if one amount is d more than the other and the total is T, the smaller is (T − d) ÷ 2.
- One letter: write the other unknown in terms of x (x + 300, x − 8, 100000 − x) and solve one equation.
- Two letters: one equation per fact; substitute one into the other.
- Special quantities (page 4): perimeter = 2(length + breadth), 7% of x = 0.07x, speed in the t-th second = u + at.
Question 1 · Bag and umbrella
Q1Priya bought a bag and an umbrella, paying ₹1100. The bag cost ₹300 more than the umbrella. What did each cost?
(പ്രിയ 1100 രൂപ കൊടുത്ത് ബാഗും കുടയും വാങ്ങി. ബാഗിന് കുടയെക്കാൾ 300 രൂപ കൂടുതലാണ്. ഓരോന്നിന്റെയും വില എത്ര?)
Put the extra ₹300 of the bag aside. What is left is shared equally.
🧠 In your head
1100 − 300 = 800, half is 400. Umbrella ₹400; bag 400 + 300 = ₹700.
✏️ One letter
✏️✏️ Two letters
Question 2 · Sum 26, difference 4
Q2The sum of two numbers is 26 and their difference is 4. Find the numbers.
The larger is the smaller plus 4. Take the 4 away from 26 and halve.
"Sum and difference" puzzles hide everywhere – two brothers' ages, two sides of a field, two teams' scores. Section 3 (page 9 of this guide) turns this into a one-line rule.
Question 3 · A rectangle's sides
Q3The perimeter of a rectangle is 40 centimetres. One side is 8 centimetres longer than the other. Find the lengths of the sides.
Half the perimeter is one length plus one breadth.
Question 4 · One wire, a square and a triangle
Q4A wire 3½ metres long is cut into two pieces. One piece is bent into a square and the other into an equilateral triangle, and all the sides of both are equal. How should the wire be cut?
The square has 4 sides, the triangle 3 – seven equal sides in all.
Here one letter does it: side s, 4s + 3s = 7s = 3.5. You could also write two letters (square piece x, triangle piece y): x + y = 3.5 and x/4 = y/3 – but the one-letter way is quicker.
Question 5 · Girls and boys
Q5A class has 4 more girls than boys. One day only 8 boys were absent, and the girls were then twice the boys present. How many girls and boys are there in the class?
Boys b. Girls b + 4. Boys present b − 8, and the girls are 2(b − 8).
Question 6 · A fraction puzzle
Q6Adding 1 to the numerator of a fraction and simplifying gives ⅓; adding 1 to the denominator gives ¼. What is the fraction?
Numerator x, denominator y. A fraction equal to ⅓ has its denominator 3 times its numerator.
Question 7 · Two investments
Q7A person invested ₹100000 in two schemes, one paying 7% and the other 6% annual interest. After a year the total interest from both was ₹6750. How much was invested in each?
If all ₹100000 earned 6%, the interest would be ₹6000. Every rupee moved to the 7% scheme earns 1 paisa more.
Banks, post-office schemes and loans all work like this: a total amount, two rates, one total interest. The same two-equation idea finds the split.
Question 8 · Speeding up
Q8An object starts with a speed of u metres/second and its speed increases by a metres/second every second, so its speed in the t-th second is u + at. Its speed in the 1st second is 5 m/s and in the 5th second 13 m/s. At what rate does the speed increase each second? What was the starting speed?
Write u + a = 5 and u + 5a = 13. What does the difference tell you?
Make your own: total and difference
Questions 1, 2 and 3 are all this puzzle in disguise. The difference must be smaller than the total, or the smaller amount would be negative.
Check yourself
- "Total and difference" (Q1–Q3): set the difference aside and halve – or write x + y = T, x − y = d.
- Count equal parts (Q4): 7 equal sides share 3½ m.
- Turn each sentence into an equation (Q5, Q6) and substitute.
- Rates and steady change (Q7, Q8) give equations like 0.07x + 0.06y and u + at – the method is the same.
Next: Section 2 – two equations and the trick of elimination ▶