Chapter 2 · ApplicationsUse it in real life

Real-World Applications പ്രയോഗങ്ങൾ

Numbers like √2 and √3 are not a classroom curiosity. They appear every time a square is measured corner to corner, every time a sheet of paper is folded in half, in every screen size and every ladder. This page shows where they turn up, how much of their decimal is really needed, and why a calculator can never show the whole number.

📖 The facts behind every application

1. The diagonal of a square room

A square room with sides 3 m: how far is it from corner to corner? The diagonal is 3 × √2 = 4.2426… m. A tape measure shows centimetres and millimetres – fractions of a metre – and the far corner never sits exactly on a mark. Everyone in the building trade simply reads 4.24 m or 4.243 m, depending on how precise the job must be.

📐 Corner to corner

The diagonal is always side × √2 – the square on the diagonal has twice the area of the room, so its side is √2 times longer. Whatever the side, the decimal never ends.

In the exam this looks like: "The side of a square is 5 m. Find the length of its diagonal correct to a centimetre." → 5 × 1.4142 = 7.071 → 7.07 m.

2. The two set squares in your geometry box

One set square has angles 45°, 45°, 90°: its two short sides are equal, so its sides are in the ratio 1 : 1 : √2. The other has angles 30°, 60°, 90°: it is half an equilateral triangle, so its sides are 1 : √3 : 2. Measure yours – the long sides are never a "nice" number of centimetres.

📏 Sides of the set squares
In the exam this looks like: "The perpendicular sides of a right triangle are 1 m and 1 m / 1 m and √3 m. Find the hypotenuse." → √2 m / √(1 + 3) = 2 m.

3. A4 paper: the √2 rectangle

An A4 sheet is 210 mm by 297 mm, and 297 ÷ 210 = 1.4142… = √2. That is no accident: a rectangle whose sides are in the ratio 1 : √2 keeps the same shape when folded in half – the half sheet (A5) is again 1 : √2. Any other ratio would change shape at every fold.

🎬 Fold an A4 sheet in half
In the exam this looks like: "The sides of a rectangle are 1 m and √2 m. Show that half of it (cut parallel to the short side) has sides in the same ratio." → half has sides √2/2 and 1; 1 ÷ (√2/2) = 2/√2 = √2 ✓ (because √2 × √2 = 2).

4. Screen sizes: the diagonal is the number they sell

A "55-inch" television is 55 inches corner to corner. Its width and height are in the ratio 16 : 9, so the diagonal of a 16 × 9 rectangle is √(16² + 9²) = √337 = 18.357… units. Width = 55 × 16 ÷ 18.357 and height = 55 × 9 ÷ 18.357 – both involve √337, so they are never exact fractions of an inch.

📺 From the diagonal to width and height
In the exam this looks like: "The perpendicular sides of a right triangle are 16 cm and 9 cm. Between which two natural numbers does the hypotenuse lie?" → √337: 18² = 324 < 337 < 361 = 19², so between 18 and 19.

5. A ladder against a wall

The foot of a ladder is a metres from the wall and its top is b metres up. The ladder is the hypotenuse: √(a² + b²). Sometimes that is a fraction (3, 4 → 5), usually it is not (1, 1 → √2; 2, 3 → √13).

🪜 How long is the ladder?

Try 3 and 4, 1.5 and 2, 0.5 and 1.5: when a² + b² is a perfect square the ladder's length is a fraction; otherwise it is a new number like √13.

In the exam this looks like: "A right triangle has perpendicular sides 2 m and 3 m. Find the hypotenuse and the perimeter correct to a centimetre." → √13 ≈ 3.606; perimeter 5 + √13 ≈ 8.61 m.

6. How many decimal places does the job need?

√2 = 1.41421356… Nobody uses all of it. A tailor marking cloth works to the centimetre, a carpenter to the millimetre, a machinist to a hundredth of a millimetre. Each needs a different number of decimal places – and each stops as soon as the error is smaller than what the tools can measure.

🎯 Error when √2 m is cut short

The error is the part of √2 that was thrown away. With 2 places (1.41) a 1 m diagonal is short by about 4 mm – fine for a tailor, not for a carpenter, who keeps 3 places (1.414, short by 0.2 mm).

In the exam this looks like: "The perimeter of a triangle is 2 + √2 m. Write it correct to a centimetre and to a millimetre." → 3.41 m and 3.414 m.

7. What your calculator is hiding

Press √2 on a calculator and you see 1.4142135 or 1.414213562. That is a rounded value – the display is simply not wide enough for a number whose digits never end. Square the displayed number and you never get back exactly 2.

🧮 Square the displayed value
In the exam this looks like: "Is 1.41421 equal to √2? Why not?" → No: 1.41421² = 1.9999899241, not 2; √2 is only approximately 1.41421 (≈).

8. The square-root spiral

Right triangles with one side 1, each built on the hypotenuse of the last, give hypotenuses √2, √3, √4, √5, … They curl into a spiral that designers, jewellers and architects use as a motif, and that looks remarkably like a snail shell.

🐚 Build the spiral

The nth triangle has sides 1, √n and √(n + 1). Only √4 = 2, √9 = 3 and √16 = 4 are natural numbers; all the others are new numbers.

In the exam this looks like: "In the fan of right triangles with 1 m sides, write the sides of the 7th triangle." → 1, √7, √8 m.

9. Doubling the cube: the Delian problem

An ancient Greek story says the citizens of Delos were told to double the volume of their cubical altar. Doubling the side gives eight times the volume; the side they needed was ∛2 ≈ 1.26 times the old one – a number that, like √2, is not a fraction, and which cannot even be drawn with ruler and compass.

🧊 Side of a cube of volume 2
In the exam this looks like: "Between which two decimals, correct to one place, does the side of a cube of volume 2 lie?" → 1.2³ = 1.728 < 2 < 2.197 = 1.3³, so between 1.2 and 1.3.

10. Fencing a triangular plot

Two plots: one is half a 30 m square cut along its diagonal (sides 30 m, 30 m, 30√2 m); the other has sides 30 m, 40 m, 50 m. Fencing is sold by the metre, so the first perimeter must be rounded before the bill can be written.

🌾 Cost of the fence
In the exam this looks like: "The perpendicular sides of a right triangle are 30 m each. Find its perimeter correct to a metre." → 60 + 30√2 = 60 + 42.426 = 102.43 → 102 m.
📜 A little history: the shattered belief (തകരുന്ന വിശ്വാസങ്ങൾ)

The followers of Pythagoras (Greece, about 2500 years ago) believed that any two lengths could be compared with whole numbers – that every ratio of lengths was a ratio a : b of natural numbers. The diagonal and the side of a square broke that belief: if diagonal : side = a : b then (a/b)² = 2, which is impossible. The story goes that Hippasus, who revealed this, was thrown into the sea. Today such pairs of lengths are called incommensurable, and the numbers that measure them – √2, √3, π – are the "new numbers" of this chapter.

11. Try these word problems

🧭 Take-away

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