Chapter 3 · Exercises 3 & 4Textbook pages 50 and 53–55

Exercises 3 & 4 – Animated Solutions ത്രികോണഭാഗം · മധ്യഭാഗം

Nine questions. The first four use "a line parallel to a side cuts the other two sides in the same ratio" (and its converse); the last five use the midpoint theorem. Read each question, try it in your notebook (use the hint if you are stuck), then press Next ▶ and watch the figure and the proof grow together.

📖 Tools you will use (page 8 of this guide)

Exercise 3 · Question 1 – pieces of the left side

Q1

In the figure, the green line is parallel to the right side of the blue triangle. The left side is 6 cm long and the base is split into 3 cm and 5 cm. Find the lengths of the two pieces of the left side.

(ഈ വര ത്രികോണത്തിന്റെ ഇടതുവശത്തെ മുറിക്കുന്ന ഭാഗങ്ങളുടെ നീളം കണക്കാക്കുക.)

The green line is parallel to the right side, so it cuts the base and the left side into the same fractions. What fraction of the base is the 3 cm piece?

🎬 Solution animation
Answer: AE = 6 × 3/8 = 2¼ cm and EC = 6 × 5/8 = 3¾ cm.

Exercise 3 · Question 2 – a parallelogram and its diagonal

Q2

In the parallelogram ABCD, the line through P on AB parallel to BC meets AC at Q, and the line through Q parallel to AB meets AD at R. Prove that (i) AP/PB = AR/RD and (ii) AP/AB = AR/AD.

The diagonal AC splits the parallelogram into two triangles, ABC and ACD. PQ is parallel to a side of the first; QR is parallel to a side of the second (why?). Apply Key idea 5 in each and compare.

🎬 Solution animation
Proof: (i) In ΔABC, PQ ∥ BC ⇒ AP/PB = AQ/QC. In ΔACD, QR ∥ DC (QR ∥ AB and AB ∥ DC) ⇒ AQ/QC = AR/RD. Hence AP/PB = AR/RD. (ii) Same fractions: AP/AB = AQ/AC and AR/AD = AQ/AC, so AP/AB = AR/AD.

Exercise 3 · Question 3 – trisecting a diagonal

Q3

In the figure, two opposite vertices of a parallelogram are joined to the midpoints of two opposite sides. Prove that these two lines divide the diagonal into three equal parts.

First show that the two lines are parallel (DMBN is itself a parallelogram). Then look at two triangles, each having one of the lines through the midpoint of a side – a 1 : 1 ratio.

🎬 Solution animation
Proof: DN = ½DC = ½AB = MB and DN ∥ MB ⇒ DMBN is a parallelogram ⇒ DM ∥ BN. In ΔABY, M is the midpoint of AB and MX ∥ BY ⇒ AX = XY. In ΔCDX, N is the midpoint of DC and NY ∥ DX ⇒ CY = YX. So AX = XY = YC.

Exercise 3 · Question 4 – two parallels in one triangle

Q4

In triangle ABC, the line through P on BC parallel to AC meets AB at Q, and the line through Q parallel to AP meets BC at R. Prove that BP/PC = BR/RP.

Both ratios can be written as BQ/QA – one from triangle ABC, the other from triangle ABP.

🎬 Solution animation
Proof: In ΔABC, QP ∥ AC ⇒ BQ/QA = BP/PC. In ΔABP, QR ∥ AP ⇒ BQ/QA = BR/RP. Therefore BP/PC = BR/RP.

Exercise 4 · Question 1 – the midpoint triangle

Q1

In the figure, the midpoints of the sides of a triangle are joined to make another triangle. How many times the perimeter of the small triangle is the perimeter of the big one? And the area?

(വലിയ ത്രികോണത്തിന്റെ ചുറ്റളവ്, ചെറിയ ത്രികോണത്തിന്റെ ചുറ്റളവിന്റെ എത്ര മടങ്ങാണ്? പരപ്പളവോ?)

Each side of the small triangle is half a side of the big one. And the three midlines cut the big triangle into four congruent pieces.

🎬 Solution animation
Answer: perimeter of the big triangle = 2 times the small one (each side is doubled); area = 4 times (four congruent triangles).

Exercise 4 · Question 2 – cutting out the middle

Q2

A paper triangle (first picture). The middle triangle formed by the midpoints is cut out (second picture). From each of the three remaining triangles the middle triangle is again cut out (third picture). (i) What fraction of the first picture's area is the second picture? (ii) And the third?

Cutting out the middle triangle removes ¼ and leaves ¾. Doing it again to every remaining piece leaves ¾ of ¾.

🎚️ Cut, and cut again

Red is paper, white is cut away. Each cut keeps ¾ of what was there.

Answer: (i) second picture = ¾ of the first; (ii) third picture = ¾ × ¾ = 9/16 of the first.

Exercise 4 · Question 3 – a rectangle inside a right triangle

Q3

A quadrilateral is drawn with the right-angle vertex of a right triangle and the midpoints of its sides as vertices. (i) Prove that it is a rectangle. (ii) What fraction of the triangle's area is the rectangle's area?

Two of its sides are midlines of the triangle – so they are parallel to the legs and half as long. A parallelogram with a right angle is a rectangle.

🎬 Solution animation (legs 6 cm and 8 cm as an example)
Answer: (i) ML ∥ CB and NL ∥ CA (midlines) ⇒ CMLN is a parallelogram with a right angle at C ⇒ a rectangle. (ii) Its sides are ½CA and ½CB, so its area is ¼·CA·CB = half the triangle's area ½·CA·CB.

Exercise 4 · Question 4 – two triangles on one line

Q4

Two points above a line are joined to its ends, making two triangles. The midpoints of the left and right sides of the two triangles are joined to make a quadrilateral. (i) Prove that it is a parallelogram. (ii) Where should the two points be for it to be (a) a rhombus (b) a rectangle (c) a square? (iii) Is everything still true if one point is above the line and the other below?

Two of the four sides are midlines of triangles standing on AB – both parallel to AB and half of it. The other two are midlines of triangles with PQ as a side.

🎬 Solution animation
🖐️ Drag P and Q – what shape do the midpoints make?

Try to make PQ equal to AB (rhombus), PQ perpendicular to AB (rectangle), or both (square). Drag Q below the line – the quadrilateral is still a parallelogram.

Answer: (i) KL and NM are midlines of ΔPAB and ΔQAB, so both are ∥ AB and = ½AB ⇒ KLMN is a parallelogram. Its other sides LM and NK are ½PQ. (ii) (a) rhombus when PQ = AB; (b) rectangle when PQ ⊥ AB; (c) square when PQ = AB and PQ ⊥ AB. (iii) Yes – nothing in the argument used "above".

Exercise 4 · Question 5 – midpoints of any quadrilateral

Q5

(i) Prove that the quadrilateral formed by joining the midpoints of the sides of any quadrilateral is a parallelogram. (ii) What must the original quadrilateral be like for the inner one to be (a) a rhombus (b) a rectangle (c) a square?

Draw one diagonal: it splits the quadrilateral into two triangles, and two of the midlines are parallel to that diagonal and half of it. The other diagonal does the same for the other two sides.

🎬 Solution animation
🖐️ Drag the corners – watch the diagonals and the inner shape

Make the diagonals equal (rhombus), perpendicular (rectangle) or both (square). Even a "dented" quadrilateral gives a parallelogram.

Answer: (i) PQ ∥ AC, PQ = ½AC (ΔABC) and SR ∥ AC, SR = ½AC (ΔADC) ⇒ PQ and SR equal and parallel ⇒ PQRS is a parallelogram. (ii) Its sides are ½AC and ½BD, parallel to the diagonals: (a) rhombus when AC = BD; (b) rectangle when AC ⊥ BD; (c) square when the diagonals are equal and perpendicular.

Check yourself

🧭 What these exercises taught

Next: Section 5 – the altitudes and medians of a triangle meet at one point ▶