Chapter 4 · Section 3 (continued)Textbook pages 79–81

Is g the Same Everywhere? The Moon ചന്ദ്രനിലെ ഗുരുത്വാകർഷണത്വരണം

On page 7 we found g = GM/R² ≈ 9.8 m/s². But R – your distance from the Earth's centre – is not the same everywhere. So is g the same at the equator and at the North Pole? Deep down a mine? High above in an aeroplane? And on the Moon? Let's find out.

📖 What you need (pages 3, 6 and 7 of this guide)

1. The Earth is not a perfect sphere (Fig 4.10)

The thinking girl asks: ഭൂഗുരുത്വാകർഷണത്വരണം ഭൂമിയിൽ എല്ലായിടത്തും ഒരുപോലെയാണോ? – Is g the same everywhere on the Earth? Look at Fig 4.10 (drawn below, with the flattening greatly exaggerated) and answer the textbook's questions.

🗺️ g map – move along the Earth from the equator to the pole

The real Earth's equatorial radius is about 6378 km and its polar radius about 6357 km – only 21 km less, so a true-to-scale picture would look perfectly round. The values of g follow the textbook: about 9.78 m/s² at the equator and 9.83 m/s² at the poles.

Textbook questions (page 79)

  1. ഭൂമി യഥാർഥ ഗോളാകൃതിയിലാണോ? Is the Earth a perfect sphere?
  2. ഭൂകേന്ദ്രത്തിൽ നിന്നുള്ള അകലം ഏറ്റവും കൂടിയ ഭാഗം ഏതാണ്? (ധ്രുവപ്രദേശം / ഭൂമധ്യരേഖാപ്രദേശം) Where is the distance from the centre greatest? (polar / equatorial region)
  3. അകലം കുറഞ്ഞ ഭാഗമോ? And where is it least?
  4. ഭൂകേന്ദ്രത്തിൽ നിന്ന് ഉപരിതലത്തിലേക്കുള്ള അകലം വ്യത്യാസപ്പെടുമ്പോൾ g യുടെ മൂല്യത്തിന് എന്തു മാറ്റമുണ്ടാകും? How does g change when the distance from the centre to the surface changes? (Check with g = GM/R².)
  5. g യുടെ മൂല്യം ഏറ്റവും കൂടുതൽ എവിടെയാണ്? Where is g greatest? (equatorial / polar region)
1. No. It is slightly flattened at the poles and bulges at the equator.
2. In the equatorial region (ഭൂമധ്യരേഖാപ്രദേശം) – about 6378 km.
3. In the polar region (ധ്രുവപ്രദേശം) – about 6357 km.
4. g = GM/R²: G and M are fixed, so a smaller R gives a bigger g and a bigger R gives a smaller g.
5. In the polar region: R is least there, so g is greatest – about 9.83 m/s². At the equator g is least – about 9.78 m/s².
⭐ Values of g (textbook page 80)

ഭൂമധ്യരേഖാ പ്രദേശത്ത് g യുടെ ഏകദേശ മൂല്യം = 9.78 m/s². ധ്രുവപ്രദേശത്ത് g യുടെ ഏകദേശ മൂല്യം = 9.83 m/s².

In the equatorial region g ≈ 9.78 m/s²; in the polar regions g ≈ 9.83 m/s². The average value used in calculations is 9.8 m/s².

📝 Teacher's note (not in the textbook)

There is a second, smaller reason why g is less at the equator: the Earth spins. A person at the equator is carried round a big circle once a day, and a little of the Earth's pull is used up keeping them on that circular path (you will meet this “centripetal force” on page 11). At the poles you just turn on the spot. Both effects – the bulge and the spin – make g smaller at the equator.

2. Down to the centre, up into the sky

Q. ഭൂകേന്ദ്രത്തിൽ വസ്തുവിനെ എല്ലാഭാഗത്തു നിന്നും ആകർഷിക്കുന്ന ബലങ്ങൾ തുല്യമായതിനാൽ അവിടെ g യുടെ മൂല്യം എത്രയായിരിക്കും? – At the centre of the Earth the object is pulled equally from all sides. What will be the value of g there?

Zero. Why: at the centre there is as much Earth above you as below, as much to the left as to the right. Each pull is cancelled by an equal pull in the opposite direction, so the total (net) pull is zero, and g = 0. (Your mass is still the same there.)
⛏️🚀 Travel from the centre of the Earth to far above it

Model used: inside a uniform Earth, g = 9.8 × (r ÷ R); outside, g = 9.8 × (R ÷ r)². (The real Earth is denser in its core, so g actually stays near 9.8–10 m/s² for the first half of the way down, but it is still zero at the centre.)

3. Why doesn't the Earth rise up to meet a falling aeroplane? (Fig 4.11)

ഗുരുത്വാകർഷണബലം എന്നത് പരസ്പരാകർഷണബലം ആണല്ലോ. Gravity is a mutual force. If an aeroplane's engines stop, the plane falls to the Earth – but the Earth does not rise up towards the plane, although it is pulled by the same force. Why? Let's calculate (textbook page 80).

Example. An aeroplane of mass 10000 kg is 10 km above the Earth. Find (a) the gravitational force between the plane and the Earth, (b) the acceleration of the plane, (c) the acceleration produced in the Earth. (M = 6 × 1024 kg, R = 6.4 × 106 m, G = 6.67 × 10−11 N m²/kg².)

The distance from the Earth's centre is R + h = 6.4 × 106 + 104 = 6.41 × 106 m. Both bodies feel the same F; use a = F/m for the plane and a = F/M for the Earth.

🎬 Solution in exam layout
Answer: (a) F = GMm/(R + h)² = (6.67 × 10−11 × 6 × 1028) ÷ (6.41 × 106)² ≈ 97400 N. (b) Plane: a = F/m = 97400 ÷ 10000 = 9.74 m/s². (c) Earth: a = F/M = 97400 ÷ (6 × 1024) = 1.6 × 10−20 m/s² = 0.000000000000000000016 m/s² – practically zero.
⭐ Same force, different accelerations (textbook page 80)

ഒരേ ബലം പ്രയോഗിക്കപ്പെടുമ്പോൾ മാസ് കൂടിയ വസ്തുക്കൾക്ക് ലഭിക്കുന്ന ത്വരണം കുറവായിരിക്കും.

When the same force acts, an object with a larger mass gets a smaller acceleration. The plane and the Earth pull each other equally, but the Earth's enormous mass makes its acceleration practically zero – so we never notice the Earth moving.

⚖️ The same 97400 N on different bodies

4. g on the Moon

The thinking boy asks: ഭൂമിയിലെയും ചന്ദ്രനിലെയും ഗുരുത്വാകർഷണ ത്വരണത്തിന്റെ മൂല്യങ്ങൾ ഒരുപോലെയാകുമോ? – Are the values of g on the Earth and on the Moon the same? The same formula g = GM/R² works for the Moon – we just use the Moon's mass and radius.

Textbook (page 81). Mass of the Moon M = 7.34 × 1022 kg, radius R = 1.74 × 106 m. Find g on the Moon and compare it with g on the Earth (9.8 m/s²).

Top: 6.67 × 7.34 and 10−11 × 1022. Bottom: 1.74² and (106)². Then divide 1.62 by 9.8.

🎬 Solution in exam layout
Answer: gMoon = GM/R² = (6.67 × 10−11 × 7.34 × 1022) ÷ (1.74 × 106)² = 48.96 × 1011 ÷ 3.0276 × 1012 = 1.617 ≈ 1.62 m/s². gMoon ÷ gEarth = 1.62 ÷ 9.8 = 0.165 ≈ 1/6. The value of g on the Moon is about one-sixth of that on the Earth.
🌍🌕 Drop a ball on the Earth and on the Moon
🚀 Real life: Chandrayaan-3

Vikram, the lander of Chandrayaan-3, touched down near the Moon's south pole on 23 August 2023. As it came down, the Moon's gravity (g = 1.62 m/s²) kept speeding it up, so its engines had to fire downwards to slow it to a gentle “soft landing”. Because the Moon's g is only about 1/6 of the Earth's, a much smaller engine thrust is enough to hover there than on Earth.

📚 Black holes (തമോഗർത്തം) – textbook box, page 81
🌐 Explore online needs internet · opens in a new tab

5. Check yourself

🧭 Summary

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