Chapter 8 · Prerequisite 4 of 4Basics for textbook page 164

Speed, Distance and Time; Light against Sound

On a monsoon evening you see a flash of lightning – and only a few seconds later you hear the thunder. Both happen at the same moment, so why the delay? Your textbook (page 164) answers with the speed of sound (ശബ്ദവേഗം) and a simple calculation: distance = speed × time. This page teaches that formula from scratch – what speed means, the units m/s and km/h, how to rearrange the formula – and then races light against sound.

📖 What you need

1. What is speed?

Speed tells you how much distance is covered in one unit of time. If a cyclist goes 50 m every 10 s, she covers 5 m in each second: her speed is 5 metres per second, written 5 m/s.

speed = distance ÷ time   (v = d ÷ t)

The SI unit of speed is the metre per second (m/s). Vehicles use kilometres per hour (km/h). The speed of sound in air is about 350 m/s – your textbook's Table 8.3 gives 347 m/s at 25 °C, and uses 350 m/s in its example.

🧪 The race to the temple gate

The race runs in real time for 10 seconds. Speeds used: walking 1.5 m/s, cycling 5 m/s, KSRTC bus 15 m/s, sound in air 350 m/s. Time taken = distance ÷ speed.

2. Units: m/s and km/h

To change between the two units, remember 1 km = 1000 m and 1 h = 60 × 60 = 3600 s:

1 km/h = 1000 m ÷ 3600 s = 1 ÷ 3.6 m/s  ·  so km/h ÷ 3.6 = m/s, and m/s × 3.6 = km/h
🧪 Speed converter

Slide all the way to 1260 km/h: that is the speed of sound in air, 350 m/s – faster than a passenger jet (about 900 km/h = 250 m/s).

Worked example 1 · The KSRTC bus

Q. A KSRTC bus travels 54 km in 1 hour on a straight highway. Find its speed in m/s.

Change the distance into metres (× 1000) and the time into seconds (1 h = 3600 s) first. Then divide.

🎬 Exam layout, step by step
Answer: v = d ÷ t = 54 000 m ÷ 3600 s = 15 m/s (check: 54 ÷ 3.6 = 15).

3. Rearranging the formula

The same three quantities can be arranged three ways. Cover the one you want in the triangle, and the other two show you what to do:

🧪 The d-v-t triangle
Find:

d on top, v and t at the bottom. Covering d leaves v × t (side by side = multiply). Covering v leaves d over t (one above the other = divide); covering t leaves d over v.

To findFormulaExample with sound in air (350 m/s)
distanced = v × tin 4 s sound travels 350 × 4 = 1400 m
speedv = d ÷ t1400 m in 4 s → 1400 ÷ 4 = 350 m/s
timet = d ÷ vto cover 700 m: 700 ÷ 350 = 2 s

4. Light against sound

Light is astonishingly fast: about 3 × 108 m/s – that is 300 000 000 m (300 000 km) every second. Sound in air covers only about 350 m in a second. So light is almost a million times faster (3 × 108 ÷ 350 ≈ 860 000). Over a few kilometres, light arrives in a few millionths of a second – practically instantly – while sound needs several seconds. That is why you see lightning, fireworks or a distant hammer blow before you hear them.

🧪 Flash and bang

The sound front moves in real time at 350 m/s. The light covers the distance in a few microseconds (1 µs = one millionth of a second) – far too short to notice. So the gap you hear is the time the sound takes.

🌴 Kerala connection – Thrissur Pooram and the monsoon

Watch the Thrissur Pooram fireworks (vedikkettu) from a kilometre away: the sky lights up first, and the boom arrives about 3 seconds later. In the monsoon, count the seconds between a lightning flash and its thunder: every 3 seconds means about 1 km (1000 m ÷ 350 m/s ≈ 2.9 s). At a cricket match in the Greenfield Stadium, Karyavattom, people in the far stands see the bat hit the ball a moment before they hear the “tock”.

Worked example 2 · The firecracker (textbook page 164)

Q. At night you see the light of a firecracker and hear its sound 3 seconds later. If the speed of sound is 350 m/s, how far away did the firecracker burst?

The light reached you almost instantly, so the sound took the full 3 s. Use distance = speed × time.

🎬 Exam layout, step by step
Answer: d = v × t = 350 × 3 = 1050 m (about 1 km). The light took only 1050 ÷ (3 × 108) = 3.5 × 10−6 s = 3.5 µs.

Worked example 3 · How far is the storm?

Q. During a thunderstorm, Meera counts 6 seconds between a lightning flash and the thunder. Taking the speed of sound as 350 m/s, find the distance of the lightning (a) in metres, (b) in kilometres.

Distance = speed × time. To change metres into kilometres, divide by 1000.

🎬 Exam layout, step by step
Answer: (a) d = 350 × 6 = 2100 m; (b) 2100 ÷ 1000 = 2.1 km.
⚠ Lightning safety: if the thunder comes less than about 30 seconds after the flash (about 10 km or closer, approx.), the storm is near – go indoors. Keep away from tall trees, open fields, water bodies and metal poles, and don't use a wired phone or stand on the terrace during the storm.
⭐ Key ideas

5. Check yourself

Next: How sound is produced – the chapter begins ▶