Model Test Paper മാതൃകാ ചോദ്യപേപ്പർ
Kerala State Syllabus · Standard IX · Mathematics Part 1
MATHEMATICS – Chapter 7: Negative Numbers (ന്യൂനസംഖ്യകൾ)
Instructions: Answer all questions. Write negative numbers with brackets when they follow a sign, for example 6 − (−4). Marks are given for correct steps even when the final answer is wrong. Section A: 8 × 1 = 8, Section B: 5 × 2 = 10, Section C: 4 × 3 = 12, Section D: 2 × 5 = 10.
SECTION A – Answer all questions8 × 1 = 8 marks
1.
−9 + 4 =
(1)2.
3 − 10 =
(1)3.
6 − (−4) =
(1)4.
(−3) × (−7) =
(1)5.
(−24) ÷ 6 =
(1)6.
−(−8) =
(1)7.
(−1)9 =
(1)(a) 1(b) −1(c) 9(d) −9
8.
A point at −3 on the number line moves 5 to the right. Its new position is .
(1)SECTION B – Answer all questions5 × 2 = 10 marks
9.
Complete the table:
(2)| x | y | x + y |
|---|---|---|
| 7 | −10 | |
| −7 | 10 | |
| −7 | −10 | |
| −4 | 4 |
10.
Find the change of position from −6 to 5, and from 5 to −6, writing each as y − x.
(2)11.
Using the reasoning of the textbook, explain why 4 − (−7) = 11.
(2)12.
Compute (−2)(−3)(−4) and (−2)(−3)(−4)(−5).
(2)13.
Find y in y = x² + 3x + 2 when x = −3 and when x = −4.
(2)SECTION C – Answer all questions4 × 3 = 12 marks
14.
Show, with x = 12, y = −5, z = −3, that (x + y)z = xz + yz. Use it to explain why (−5) × (−3) must be 15.
(3)15.
Find two pairs of integers (x, y) with x positive, y negative and x + y = 2; and two pairs with x negative, y positive and x + y = −2.
(3)16.
Find z = xy − yx for
(3)- x = 6, y = −3
- x = −6, y = −3
17.
A point moves along a line at 8 m/s. We start watching when it passes O. Find its position
(3)- 3 seconds later, moving right
- 3 seconds earlier, moving right
- 3 seconds earlier, moving left.
SECTION D – Answer all questions2 × 5 = 10 marks
18.(5)
- For four consecutive natural numbers a, b, c, d, show using algebra that a − b − c + d = 0.
- What is a + b − c − d?
- Check both with 10, 11, 12, 13 and with −1, −2, −3, −4.
- Find all pairs of integers (x, y) with x² + y² = 25.
19.
A ball is thrown straight up at 29.4 m/s; its speed decreases by 9.8 m/s every second.
(5)- Find its speed after 1 second and after 2 seconds.
- When does it stop rising?
- Taking upward speed as positive, v = 29.4 − 9.8t. Find v when t = 5 and say what it means.
- Why is one equation enough when we use negative numbers?
- Find ½(1 + (−1)n) for n = 7 and n = 10.