Chapter 4 · Section 3Textbook pages 77–79

Acceleration due to Gravity ഭൂഗുരുത്വാകർഷണത്വരണം

A force that keeps acting makes an object speed up – it gives it an acceleration (ത്വരണം). The Earth's pull keeps acting on every falling object. So how fast does a falling object speed up? Does a heavy stone speed up faster than a light one? Here you find the famous number g = 9.8 m/s² and see why heavy and light things fall together.

📖 What you need (pages 1, 4 and 6 of this guide)

1. Why does a coconut fall? (Fig 4.7)

ഭൂമിയുടെ ആകർഷണബലം കാരണമല്ലേ തെങ്ങിൽ നിന്നും ഞെട്ടറ്റുപോയ തേങ്ങ താഴോട്ട് തന്നെ പതിക്കുന്നത്? A coconut that breaks off its stalk falls straight down because of the Earth's pull. Nothing balances that pull, so it is an unbalanced force (അസന്തുലിത ബലം), and an unbalanced force produces acceleration. Watch the coconut's position every 0.25 s.

🥥 Falling coconut – strobe picture

The gaps between the images grow: in each quarter-second the coconut covers more distance than in the one before. That is what acceleration looks like.

⚠️ Kerala safety note

A coconut (about 1.5 kg) falling from a 15 m tree reaches about 17 m/s – over 60 km/h – in under 2 seconds. Never stand or park under a coconut tree with ripe nuts, especially on a windy monsoon day.

2. Activity – drop a light and a heavy object together

ഒരു നിശ്ചിത ഉയരത്തിൽ നിന്ന് മാസ് കുറഞ്ഞ വസ്തുവും മാസ് കൂടിയ വസ്തുവും ഒരുമിച്ചു താഴേക്ക് പതിപ്പിക്കുക. – From the same height, let a light object and a heavy object fall together (textbook page 77).

⚠ Real experiment: drop only from shoulder height or a chair held steady by an adult – never from a balcony or terrace – and make sure nobody's feet are underneath. Use a small stone and a rubber or paper ball, not glass.
🎬 Virtual lab: the activity step by step
🗼 Drop tower – with and without air
Height (m)AirIron ball 2 kg: time (s)Plastic ball 3 g: time (s)

Model: without air both follow s = ½ g t² exactly. With air, air resistance grows with speed; it hardly matters for the iron ball but holds back the very light ball (which can never go faster than about 9 m/s). Try 5 m and 50 m with air ON.

Q. ഏതാണ് ആദ്യം എത്തിയത്? – Which one reached the ground first?

Both reached (almost) together. Why: from a small height the air hardly affects a stone or a ball, so both fall with the same acceleration.

Q. ഏതിനായിരിക്കും കൂടുതൽ ത്വരണം ഉണ്ടായത്? – Which one had more acceleration?

Neither – the accelerations were equal. Why: they started together from rest, covered the same distance in the same time, so they speeded up at the same rate. The Earth pulls the heavy one harder, but it also needs more force to speed it up (F = ma): the two effects cancel.

By Newton's second law F = ma. If F is the Earth's attractive force and m the mass of the object, then a is the acceleration caused by the Earth's attraction:

⭐ Acceleration due to gravity (textbook page 78)

ഭൂഗുരുത്വാകർഷണബലത്താൽ വസ്തുക്കൾക്കുണ്ടാവുന്ന ത്വരണം ഭൂഗുരുത്വാകർഷണത്വരണം (acceleration due to gravity) എന്ന് അറിയപ്പെടുന്നു. ഇത് g എന്ന അക്ഷരം കൊണ്ടാണ് സൂചിപ്പിക്കുന്നത്.

The acceleration produced in objects by the Earth's gravitational force is called the acceleration due to gravity. It is written with the letter g.

3. A formula for g (Fig 4.8)

🎬 From Newton's two laws to g = GM/R²

Q. g യുടെ യൂണിറ്റെന്ത്? – What is the unit of g?

m/s² (metre per second squared). Why: g is an acceleration. Check from the formula: GM/R² has unit (N m²/kg²) × kg ÷ m² = N/kg = (kg m/s²)/kg = m/s². So 1 N/kg = 1 m/s².

Q. ഈ സമവാക്യത്തിൽ വസ്തുവിന്റെ മാസ് ഉൾപ്പെട്ടിട്ടുണ്ടോ? – Is the mass of the object in this equation?

No. g = GM/R² contains only G, the Earth's mass M and the Earth's radius R. The object's mass m cancelled out. So g does not depend on the mass of the falling object – and that is why objects of different mass, dropped together from the same height, reach the ground together.
📚 Distance from the Earth's centre to a coconut on the tree (textbook box, page 78)

തെങ്ങിലുള്ള തേങ്ങയിലേക്ക് ഭൂകേന്ദ്രത്തിൽ നിന്നുള്ള ദൂരം എങ്ങനെ കണക്കാക്കാം? Strictly, the distance is the Earth's radius plus the height of the tree: R + h. But R is so large (6400 km = 64,00,000 m) that adding about 15 m makes no noticeable difference.

Check: with R = 6.4 × 106 m, g = 9.77051 m/s²; with R + 15 m, g = 9.77046 m/s². The difference is only 0.00005 m/s² – about five parts in a million.

4. Mango and leaf, paper and coin

Q. മാവിൽ നിന്ന് മാങ്ങയും ഇലയും ഒരേ സമയം പതിക്കാൻ തുടങ്ങിയാൽ അവ ഒരുമിച്ച് താഴെ എത്തുമോ? എന്തായിരിക്കും കാരണം? – If a mango and a leaf start falling from a mango tree at the same time, will they reach the ground together? What could be the reason?

No – the mango lands first; the leaf flutters down slowly. Why: not because g is different – g is the same for both – but because the air pushes back on the light, wide leaf much more strongly (compared with its weight) than on the compact, heavy mango.

Test the idea with the textbook's activity: ഒരു കടലാസ് കഷണവും ഒരു നാണയവും ഒരേ ഉയരത്തിൽ നിന്ന് ഒരുമിച്ച് താഴോട്ട് ഇടുക. … ഇതേ കടലാസ് ചുരുട്ടിയ ശേഷം പ്രവർത്തനം ആവർത്തിക്കുക. – drop a piece of paper and a coin together; then crumple the same paper and repeat.

🎬 Virtual lab: paper and coin
🧪 How much does crumpling matter?
Paper shapeCoin: time (s)Paper: time (s)Paper lands later by (s)

Q. എന്ത് നിരീക്ഷിക്കുന്നു? … എന്ത് വ്യത്യാസമാണ് ഇപ്പോൾ നിരീക്ഷിച്ചത്? – What do you observe? What difference did you see after crumpling?

Flat paper: the coin lands first; the paper sways and lands much later. Crumpled paper: they land almost together. The paper's mass did not change – only its shape. So the difference is caused by the effect of air (വായു ചെലുത്തുന്ന സ്വാധീനം). That is why leaves, feathers and paper fall slowly.

5. The feather and coin experiment (Fig 4.9)

വായു നീക്കം ചെയ്യാനുള്ള ഉപായം കണ്ടെത്തിയതോടെ ഈ നിഗമനം പരീക്ഷണങ്ങളിലൂടെ തെളിയിക്കപ്പെട്ടു. Once people could pump air out of a container, this idea was proved directly. This is the feather and coin experiment (തൂവലും നാണയവും പരീക്ഷണം).

🎬 Feather and coin in a long tube – with air, then without
🌕 It was done on the Moon!

The Moon has no air. In 1971 the Apollo 15 astronaut David Scott held a hammer and a falcon feather at the same height on the Moon and let go. Both landed together, live on television – exactly as this page predicts. (On the Moon they fall more slowly than on Earth, because the Moon's g is smaller – page 8.)

6. Calculating g for the Earth

Textbook (page 79): ഭൂമിയിലെ g യുടെ മൂല്യം കണക്കാക്കി നോക്കാം. – Calculate the value of g on the Earth. Mass of the Earth M = 6 × 1024 kg, radius R = 6.4 × 106 m.

Use g = GM/R². Multiply 6.67 × 6 in the top and 6.4 × 6.4 in the bottom; add the powers of ten in the top (−11 + 24) and double the power in the bottom ((106)² = 1012).

🎬 Solution in exam layout
Answer: g = GM/R² = (6.67 × 10−11 × 6 × 1024) ÷ (6.4 × 106)² = 40.02 × 1013 ÷ 40.96 × 1012 = 9.77 ≈ 9.8 m/s².
🧮 g calculator – any planet or moon

Jupiter has no solid surface; books quote 23 to 25 m/s² depending on the level and on its fast spin. The textbook uses 23.1 m/s². The calculator uses only g = GM/R².

🌐 Explore online needs internet · opens in a new tab

7. Check yourself

🧭 Summary

Next: Is g the same everywhere? g on the Moon ▶