Chapter 5 · Section 4Textbook pages 102–103

Principle of Floatation പ്ലവനതത്വം

A stone sinks, a piece of wood floats. A sheet of aluminium foil floats as a boat but sinks as a crumpled ball. A steel ship floats while an iron nail sinks. On this page one simple rule – the principle of floatation – explains all of them, and finally answers the question from the opening page.

📖 What you need (pages 5–7 of this guide)

1. Wood and wax in the overflow jar (Table 5.6)

Repeat the overflow-jar experiment of page 7 with a wooden block (മരക്കട്ട) and a wax block (മെഴുകുകട്ട) instead of the stone and the glass slab, and complete Table 5.6.

🧪 Virtual lab: objects that float – Table 5.6
Table 5.6 – sample readings (your real readings will differ slightly)
Object വസ്തുWeight in air W₁ (N)Weight in water W₂ (N)Buoyant force W₁ − W₂ (N)Weight of displaced water (N)

Sample blocks (approx.): wood 50 g, density ≈ 650 kg/m³ (teak-like); wax 45 g, density ≈ 900 kg/m³. Once the block floats, the string goes slack and the balance reads 0.

Q. വസ്തുവിന്റെ വായുവിലെ ഭാരവും ആദേശം ചെയ്ത ജലത്തിന്റെ ഭാരവും തമ്മിലുള്ള ബന്ധം എന്താണ്? – What is the relation between the weight of the object in air and the weight of the water it displaced?

They are equal: wood 0.49 N in air, displaced water 0.49 N; wax 0.441 N and 0.441 N. Why: a floating object sinks just until the water it pushes aside weighs as much as itself – then the buoyant force balances its weight, and the spring balance has nothing left to hold (W₂ = 0).
⭐ Key idea (textbook page 102) – Principle of floatation (പ്ലവനതത്വം)

ഒരു വസ്തു ദ്രവത്തിൽ പൊങ്ങിക്കിടക്കുമ്പോൾ വസ്തുവിന്റെ ഭാരവും വസ്തു ആദേശം ചെയ്യുന്ന ദ്രവത്തിന്റെ ഭാരവും തുല്യമായിരിക്കും. ഇതാണ് പ്ലവനതത്വം.

When an object floats in a fluid, the weight of the object is equal to the weight of the fluid it displaces. This is the principle of floatation.

⚖️ Sink or float? (textbook page 102)

ഒരു ദ്രവത്തിൽ മുങ്ങിക്കിടക്കുന്ന വസ്തുവിൽ അനുഭവപ്പെടുന്ന പ്ലവക്ഷമബലം വസ്തുവിന്റെ ഭാരത്തെക്കാൾ കുറവായിരിക്കും. എന്നാൽ ദ്രവത്തിൽ പൊങ്ങിക്കിടക്കുന്ന വസ്തുവിൽ അനുഭവപ്പെടുന്ന പ്ലവക്ഷമബലം വസ്തുവിന്റെ ഭാരത്തിന് തുല്യമായിരിക്കും.

2. Float-or-sink lab – how much stays under?

For a floating object, buoyant force = weight: ρliquid × Vunder × g = ρobject × V × g. Cancel g:

fraction under the liquid = Vunder ÷ V = ρobject ÷ ρliquid

If ρobject is bigger than ρliquid, even the whole volume cannot displace enough liquid – the object sinks.

🧪 Drop a 1000 cm³ block into a liquid

Values marked ≈ are approximate. Try ice in water (about 92 % under – icebergs!), wax in kerosene, and iron in mercury (it floats!).

3. Activity – the aluminium foil boat (Fig 5.7)

Take a piece of aluminium foil about 15 cm long and 10 cm wide, shape it like a boat and put it on the water surface. What do you observe? Put a 100 g weight in the boat. Why doesn't the boat sink? Then crumple the same foil into a tight ball and put it on the water.

🎬 Foil boat and foil ball, step by step

Sample values (approx.): kitchen foil 0.016 mm thick, so the 15 cm × 10 cm sheet has a volume of 0.24 cm³ and a mass of about 0.65 g. The boat is folded to a 10 cm × 5 cm base with 2.5 cm high sides.

Textbook questions (page 102)

  1. What do you observe when the foil boat is put on the water?
  2. ബോട്ട് മുങ്ങാത്തത് എന്തുകൊണ്ടായിരിക്കും? Why doesn't the boat sink even with the 100 g weight?
  3. What happens to the same foil crumpled into a ball? Why?
1. It floats, almost entirely above the water.
2. Shaped like a boat, the foil displaces a weight of water equal to its own weight. With the weight inside, it sinks a little deeper (about 2 cm here) and displaces water equal to the total weight of the boat and the weight (about 100.65 g of water) – so it still floats.
3. It sinks. Crumpled, it can push aside only about its own metal volume (≈ 0.24 cm³ of water, weighing ≈ 0.24 gwt) – much less than its weight (≈ 0.65 gwt). The buoyant force is less than the weight. Why: the volume of water displaced by the boat-shaped foil is much greater than that displaced by the crumpled foil.
🚢 The opening question answered – nail vs ship

ഇരുമ്പാണി ജലത്തിൽ താഴ്ന്നുപോകുമെങ്കിലും ഇരുമ്പ് കൊണ്ടുണ്ടാക്കിയ കപ്പൽ സമുദ്രജലത്തിൽ പൊങ്ങിക്കിടക്കുന്നതിന് കാരണം വിശദീകരിക്കാമല്ലോ. – Explain why an iron nail sinks but a ship made of iron floats on the sea.

A 5 g iron nail has a volume of only about 0.64 cm³, so even fully under water it displaces just 0.64 g of water: buoyant force (0.64 gwt) < weight (5 gwt) → it sinks. A ship is the foil boat on a giant scale: its steel is shaped into a hollow hull full of air, so it can push aside an enormous volume of water. It settles until the weight of the sea water displaced equals the ship's whole weight – then buoyant force = weight and it floats (principle of floatation).

4. Loading a ship – fresh water and sea water

🧪 Load the cargo ship (simplified box-shaped hull)

Model (approx.): hull 200 m long, 30 m wide, 15 m high, empty mass 20 000 tonnes. Fresh water 1000 kg/m³, sea water 1025 kg/m³. The depth of the hull under water is called the draught.

Think. Why does a ship rise a little when it sails from the river into the sea? And why does it rise when its cargo is unloaded at Kochi port?

In both cases the ship must displace a weight of water equal to its own weight. Sea water is denser, so a smaller volume of it has that weight → the ship rises. After unloading, the ship's weight is smaller, so it needs to displace less water → it rises.
🌴 Kerala connection
⚠ Never lean over a well or play near deep water; do water experiments in a bucket or tub, with an adult nearby. On any boat, wear the life jacket and never stand on the edge.

5. Textbook questions (page 103)

Q1. തടാകത്തിൽ സ്ഥിതിചെയ്യുന്ന ഒരു ബോട്ട് 6000 kg ജലം ആദേശം ചെയ്യുന്നു. ബോട്ടിൽ അനുഭവപ്പെടുന്ന പ്ലവക്ഷമബലം എത്രയായിരിക്കും? – A boat on a lake displaces 6000 kg of water. What is the buoyant force on the boat?

Archimedes: buoyant force = weight of the water displaced. Weight = mass × g (or simply “6000 kg of water weighs 6000 kgwt”).

🎬 Solution in exam layout
Answer: buoyant force = weight of 6000 kg of water = 6000 kgwt = 6000 × 9.8 = 58 800 N. (The boat floats, so its own weight is also 6000 kgwt.) More solved questions: page 10 ▶

Q2. വായുവിൽ 0.45 kgwt ഭാരമുള്ള ഒരു വസ്തു മുഴുവനായും ജലത്തിൽ മുങ്ങിയിരിക്കുമ്പോഴുള്ള ഭാരം 0.31 kgwt ആണ്. എങ്കിൽ താഴെ കൊടുത്തവ കണ്ടെത്തുക. – An object weighs 0.45 kgwt in air and 0.31 kgwt when fully immersed in water. Find (a) ഭാരനഷ്ടം the loss of weight, (b) പ്ലവക്ഷമബലം the buoyant force, (c) ആദേശം ചെയ്ത ജലത്തിന്റെ ഭാരം the weight of the displaced water.

Loss = W₁ − W₂. Then use page 5 (buoyant force = loss of weight) and page 7 (buoyant force = weight of displaced water).

🎬 Solution in exam layout
Answer: (a) loss of weight = 0.45 − 0.31 = 0.14 kgwt; (b) buoyant force = 0.14 kgwt; (c) weight of displaced water = 0.14 kgwt (= 0.14 × 9.8 = 1.372 N). More: page 10 ▶
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6. Check yourself

🧭 Summary

Next: Relative density, hydrometer and lactometer ▶