Model Test – Solved ഉത്തരങ്ങൾ
Every question of the model paper, in the same order, with the full answer, the marking scheme, an animated dot diagram or orbit model for the longer questions, and a link to the page where the idea is taught. Try each one again before you open the answer, and mark your own paper honestly.
In the orbit models the nucleus is a blue disc showing protons and neutrons (for example 17p 18n), the shells are orange rings and the electrons green dots; an electron that has just been received is red. In the electron dot diagrams (ഇലക്ട്രോൺ ഡോട്ട് ഡയഗ്രം) only the outermost electrons are drawn: • dots for one atom and × crosses for the other, so you can see where each shared electron came from. Ions are written in square brackets with the charge at the top right; in a covalent bond the circles of the two atoms overlap and the shared pairs sit in the overlap.
Rules used everywhere: octet = 8 outermost electrons (duplet 2 for H, He); metal + non-metal → transfer → ionic; non-metal + non-metal → sharing → covalent; electronegativity difference ≥ 1.7 → ionic, < 1.7 → covalent; criss-cross the valencies (charges) and simplify.
💡 Work out all four differences – which one is at least 1.7?
Differences: C–S 2.58 − 2.55 = 0.03; N–H 3.04 − 2.20 = 0.84; Li–Cl 3.16 − 0.98 = 2.18; P–Cl 3.16 − 2.19 = 0.97. Only Li–Cl is 1.7 or more → ionic (അയോണിക ബന്ധനം). Lithium is a metal and chlorine a non-metal.
Marking: 1 mark for (c).
📖 Review this on Page 8 · The 1.7 rule
💡 Cation or anion – which one is negative?
Gaining electrons gives more electrons than protons → a negative ion, an anion. Atoms that lose electrons become positive ions, cations.
Marking: 1 mark.
📖 Review this on Page 4 · Cations and anions
💡 Count the electrons left in each ion.
Na+ (11 − 1 = 10 electrons), Mg2+ (12 − 2 = 10) and F− (9 + 1 = 10) all have 2, 8. K+ has 19 − 1 = 18 electrons: 2, 8, 8 – the configuration of argon.
Marking: 1 mark for (d).
📖 Review this on Page 5 · Ions and their configurations · Page 2 · Charges
💡 Two non-metals …
Hydrogen and sulphur are both non-metals; the difference is 2.58 − 2.20 = 0.38, less than 1.7 → covalent bond. (MgO: 3.44 − 1.31 = 2.13 → ionic.)
Marking: 1 mark.
📖 Review this on Page 7 · Covalent compounds · Page 8 · Electronegativity
💡 How many electrons does it need to reach 8?
Sulphur is 2, 8, 6. It needs 8 − 6 = 2 more electrons for an octet, so its valency (സംയോജകത) is 2.
Marking: 1 mark.
📖 Review this on Page 9 · Valency
💡 Which one has no metal in it?
KCl (3.16 − 0.82 = 2.34), CaO (3.44 − 1.00 = 2.44) and LiF (3.98 − 0.98 = 3.00) are ionic – a metal with a non-metal, difference ≥ 1.7. PCl3 is made of two non-metals: 3.16 − 2.19 = 0.97 < 1.7 → covalent.
Marking: ½ mark for PCl3, ½ mark for the reason.
📖 Review this on Page 8 · Electronegativity table · Page 7 · Ionic vs covalent
💡 The total charge of a salt is zero.
Ions: Ca2+ and NO3−. Write Ca NO3, swap the charge numbers → Ca1(NO3)2. Omit the 1 and keep the brackets because the radical is taken twice: Ca(NO3)2. Check: (+2) + 2 × (−1) = 0.
Marking: 1 mark for (c).
📖 Review this on Page 10 · Salts and radicals
💡 Three of the four describe ionic compounds.
Covalent compounds are generally insoluble in water but soluble in organic solvents (kerosene, carbon tetrachloride, benzene); they have low melting points and do not conduct. The other three are properties of ionic compounds.
Marking: 1 mark for (c).
📖 Review this on Page 7 · Properties of covalent compounds
💡 Metal → loses; non-metal → gains.
(a) Potassium (2, 8, 8, 1) has 1 outermost electron and gives it away: K → K+ + 1e−. Sulphur (2, 8, 6) needs 2 electrons: S + 2e− → S2−.
(b) K+: 19 − 1 = 18 electrons → 2, 8, 8; S2−: 16 + 2 = 18 electrons → 2, 8, 8. Both have the octet of argon (അഷ്ടകവിന്യാസം). The protons do not change: 19 and 16.
Marking: (a) ½ + ½; (b) configurations ½, argon ½.
📖 Review this on Page 4 · Fig 3.1, 3.2 equations · Page 5 · Mg²⁺ and O²⁻
💡 Draw it like water – sulphur is in the same group as oxygen.
Sulphur (2, 8, 6) has 6 outermost electrons (×) and needs 2; each hydrogen has 1 (•) and needs 1. S shares one pair with each H.
Sulphur now has 8 electrons around it (2 shared pairs + 2 lone pairs) and each hydrogen 2 (duplet). Two single bonds: H–S–H.
Marking: diagram 1½ (shared pairs ½ each, lone pairs ½), number of bonds ½.
📖 Review this on Page 7 · H₂O, Fig 3.11 (same pattern)
💡 Always larger − smaller, then compare with 1.7.
(a) Li–O: 3.44 − 0.98 = 2.46. 2.46 ≥ 1.7 → ionic.
(b) S–O: 3.44 − 2.58 = 0.86. 0.86 < 1.7 → covalent (a polar covalent bond; oxygen carries δ−).
Marking: (a) difference ½, type ½; (b) difference ½, type ½.
📖 Review this on Page 8 · Fig 3.12 and the 1.7 rule
💡 Al₂O₃ works the same way.
(a) Al: 2, 8, 3 → gives 3 electrons → valency 3. S: 2, 8, 6 → takes 2 → valency 2.
(b) Write Al S (less electronegative first), swap the valencies as subscripts: Al2S3. 2 and 3 have no common factor → Al2S3 (aluminium sulphide).
Marking: (a) ½ + ½; (b) 1 mark.
📖 Review this on Page 9 · Valency finder · Page 10 · Al₂O₃ step by step
💡 Ions attract strongly; molecules attract weakly.
(a) An ionic crystal (ക്രിസ്റ്റലുകൾ) is held together by the strong electrostatic force of attraction between oppositely charged ions (Na+ and Cl−) on all sides. A lot of energy is needed to pull them apart, so the melting point (ഉരുകൽനില) is very high.
(b) Covalent compounds generally have low melting and boiling points: the forces between their molecules are weak, so naphthalene slowly turns into vapour at room temperature – it is volatile. (Ionic compounds are non-volatile.)
Marking: (a) 1 mark; (b) 1 mark.
📖 Review this on Page 5 · Properties of ionic compounds, crystal lab · Page 7 · Properties of covalent compounds
(b) Draw the electron dot diagram to show the formation of calcium chloride.
(c) How many electrons and protons are there in the calcium ion? What is its charge?
💡 One calcium atom has 2 electrons to give; one chlorine needs only 1.
(a) Ca: 2, 8, 8, 2; Cl: 2, 8, 7.
(b) Calcium gives its 2 outermost electrons (•), one to each of two chlorine atoms (7 × each):
Ca2+ (2, 8, 8) and two Cl− (2, 8, 8) → CaCl2, ionic (3.16 − 1.00 = 2.16).
(c) Calcium ion: 20 − 2 = 18 electrons, 20 protons (unchanged) → charge 20 − 18 = +2.
Marking: (a) ½ + ½; (b) 1 mark (two Cl ½, brackets and charges ½); (c) 1 mark.
📖 Review this on Page 5 · Fig 3.5, Table 3.6 · Page 4 · Dot diagrams
(b) How many electron pairs does carbon share with each oxygen atom? Name this type of bond.
(c) Each C–O bond is polar (difference 0.89), yet the CO2 molecule is non-polar. Why?
💡 Each oxygen needs 2 more – how many pairs per side?
(a) C (2, 4) has 4 outermost electrons (•) and needs 4; each O (2, 6) has 6 (×) and needs 2.
(b) Carbon shares 2 pairs with each oxygen → two double bonds (ദ്വിബന്ധനം): O=C=O (4 shared pairs in all). Every atom now has 8.
(c) The molecule is straight (linear, ജ്യാമിതീയ ആകൃതി): the two oxygens pull the shared electrons equally in opposite directions, so the pulls cancel and the molecule as a whole is non-polar.
Marking: (a) 1 mark; (b) 2 pairs ½, double bond ½; (c) 1 mark.
📖 Review this on Page 6 · O₂ double bond, Fig 3.8 · Page 8 · Shape box
| Positive ion | Negative ion | Formula of the salt | Name |
|---|---|---|---|
| K+ | SO42− | (i) …… | potassium sulphate |
| Al3+ | SO42− | (ii) …… | aluminium sulphate |
| Mg2+ | CO32− | (iii) …… | magnesium carbonate |
| Al3+ | PO43− | (iv) …… | aluminium phosphate |
| (v) …… | CO32− | (NH4)2CO3 | ammonium carbonate |
| Na+ | (vi) …… | Na3PO4 | sodium phosphate |
💡 Write the two charge numbers crosswise; divide if you can.
| Positive ion | Negative ion | Formula of the salt | Name |
|---|---|---|---|
| K+ | SO42− | (i) K2SO4 | potassium sulphate |
| Al3+ | SO42− | (ii) Al2(SO4)3 | aluminium sulphate |
| Mg2+ | CO32− | (iii) MgCO3 | magnesium carbonate |
| Al3+ | PO43− | (iv) AlPO4 | aluminium phosphate |
| (v) NH4+ | CO32− | (NH4)2CO3 | ammonium carbonate |
| Na+ | (vi) PO43− | Na3PO4 | sodium phosphate |
Positive ion first, swap the charge numbers, simplify by the common factor, omit 1, and put a radical in brackets when it is taken more than once. Check: the total charge is zero – e.g. Al2(SO4)3: 2 × (+3) + 3 × (−2) = 0; MgCO3: Mg2(CO3)2 ÷ 2.
Marking: ½ mark for each blank.
📖 Review this on Page 10 · Salt table, criss-cross machine
(b) Find the electronegativity difference of the N–H bond. Draw the bond showing the partial charges δ+ and δ−.
(c) Ammonia molecules are held to one another and to water molecules by hydrogen bonds. What is hydrogen bonding?
💡 Same atoms → non-polar. Symmetric shape → non-polar.
(a) Polar (പോളാർ തന്മാത്രകൾ): H2O, NH3, HCl. Cl2 has two identical atoms (equal pull); CO2 has polar bonds but its shape cancels them.
(b) 3.04 − 2.20 = 0.84 → polar covalent. Nitrogen attracts the shared pair more: δ+H–Nδ−.
(c) Hydrogen bonding (ഹൈഡ്രജൻ ബന്ധനം): when hydrogen is covalently bonded to a highly electronegative atom (F, O or N), it gets a δ+ charge and is attracted by an electronegative atom of the same or another molecule. It is an intermolecular force (അന്തർതന്മാത്രാബലങ്ങൾ).
Marking: 1 mark each part ((a) all three ½, none wrong ½; (b) difference ½, δ ½).
📖 Review this on Page 8 · Polar nature, hydrogen bonding box
(a) Write the electron configurations of all five. Which of them does not usually form compounds? Why?
(b) Which element forms a positive ion by losing two electrons? Write the equation.
(c) Write the formula of the compound formed by J and D.
(d) Draw the electron dot diagram for the formation of the compound of A and E. What type of bond is formed?
(e) Find the nature of the bond in DE3. Which atom carries the partial negative charge?
💡 Write the five configurations first – everything follows from them.
(a) A 2, 1; D 2, 5; E 2, 7; G 2, 8, 8; J 2, 8, 8, 2. G already has 8 electrons in its outermost shell (octet) – it is stable, a noble gas, and does not usually react.
(b) J (2, 8, 8, 2) loses its 2 outermost electrons: J → J2+ + 2e− (J2+ 2, 8, 8).
(c) Valency of J = 2 (gives 2); D (2, 5) takes 3 → valency 3. Criss-cross: J3D2.
(d) A gives its one electron to E: A+ (2, like helium) and E− (2, 8). Difference 3.98 − 0.98 = 3.00 ≥ 1.7 → ionic bond; formula AE.
(e) 3.98 − 3.04 = 0.94 < 1.7 → covalent (polar). E, the more electronegative atom, carries δ−; D carries δ+.
Real elements: A Li, D N, E F, G Ar, J Ca – J3D2 is calcium nitride, AE lithium fluoride, DE3 nitrogen trifluoride.
Marking: 1 mark for each part (½ + ½ where there are two answers).
📖 Review this on Page 3 · Octet checker · Page 9 · Valency · Page 4 · Dot diagrams · Page 8 · δ+ and δ−
(b) Potassium (Z = 19) and chlorine (Z = 17) form potassium chloride. Write the equations for the formation of its ions.
(c) Using the electronegativity values, show that potassium chloride is ionic and that the C–H bonds in glucose are covalent. Why does the glucose solution not light the bulb?
(d) Common salt dissolves in water but not in coconut oil, while grease dissolves in kerosene. Explain.
(e) Water is called the universal solvent. Which feature of the water molecule helps it to dissolve salt? Draw a water molecule showing δ+ and δ−.
💡 Ions that can move → current. No ions → no current.
(a) Salt is ionic. In the solution its ions (Na+, Cl−, K+) are free to move and carry the current. In the dry crystal the ions are held fixed in place – ionic compounds conduct only when molten or dissolved.
(b) K → K+ + 1e− (2, 8, 8, 1 → 2, 8, 8); Cl + 1e− → Cl− (2, 8, 7 → 2, 8, 8); K+ + Cl− → KCl.
(c) K–Cl: 3.16 − 0.82 = 2.34 ≥ 1.7 → ionic. C–H: 2.55 − 2.20 = 0.35 < 1.7 → covalent. Glucose is a covalent compound; it dissolves as whole molecules and forms no ions, so there is nothing to carry the current.
(d) Ionic compounds are generally soluble in polar solvents (പോളാർ ലായകങ്ങൾ) like water, not in oils. Grease is a covalent substance; covalent compounds dissolve in organic solvents such as kerosene (മണ്ണെണ്ണ) but not in water.
(e) Water is a polar molecule: O (3.44) pulls the shared pairs from H (2.20), so O is δ− and each H is δ+. The δ− oxygen attracts Na+ and the δ+ hydrogens attract Cl−, pulling the ions out of the crystal. (Hydrogen bonding between water molecules also explains its other special properties.)
Marking: 1 mark for each part (½ + ½ where there are two answers).
📖 Review this on Page 5 · Properties of ionic compounds · Page 12 · Conductivity lab · Page 8 · Water and hydrogen bonds · Page 13 · Applications
Marks summary
| Section | Questions | Marks each | Total | Topics |
|---|---|---|---|---|
| A | 1–8 | 1 | 8 | 1.7 rule, anion, ions like neon, ionic : covalent, valency of S, odd one out, Ca(NO₃)₂, covalent properties |
| B | 9–13 | 2 | 10 | ion formation equations (K, S), dot diagram of H₂S, bond type of Li₂O and SO₂, Al₂S₃ by criss-cross, melting points and volatility |
| C | 14–17 | 3 | 12 | formation of CaCl₂, dot diagram and shape of CO₂, salts with radicals, polarity and hydrogen bonding |
| D | 18–19 | 5 | 10 | five elements with letters, Kerala case study on ORS and conductivity |
| Total | 40 | |||
- Cool-off (15 min) – read the whole paper. Mark the dot diagrams to draw (Q10, Q14, Q15, Q18) and the questions that need the electronegativity table (Q1, Q4, Q6, Q11, Q17, Q18, Q19).
- Section A – about 10 minutes. One word or one letter; give the reason in Q6.
- Section B – about 20 minutes. Write the configuration first, then the equation, the diagram or the formula.
- Section C – about 25 minutes. Draw diagrams neatly with a pencil: dots for one atom, crosses for the other, brackets and charges for ions.
- Section D – about 25 minutes. In Q18 first write all five configurations beside the question; in Q19 underline the substances in the passage and decide ionic or covalent for each.
- Checking – keep 10 minutes: protons unchanged in every ion? Charges + for metals, − for non-metals? Formulae simplified and radicals in brackets? Larger − smaller in every difference?
Count your marks: 32 or more – excellent; 24–31 – good, revise the pages linked under the questions you missed; below 24 – go back through pages 3 to 10 with their labs and do the scored quiz again. Then return to the chapter home and tick off what you have learned.