Chapter 3 · Solved paper40 marks

Model Test – Solved ഉത്തരങ്ങൾ

Every question of the model paper, in the same order, with the full answer, the marking scheme, an animated dot diagram or orbit model for the longer questions, and a link to the page where the idea is taught. Try each one again before you open the answer, and mark your own paper honestly.

📐 How the figures are drawn

In the orbit models the nucleus is a blue disc showing protons and neutrons (for example 17p 18n), the shells are orange rings and the electrons green dots; an electron that has just been received is red. In the electron dot diagrams (ഇലക്ട്രോൺ ഡോട്ട് ഡയഗ്രം) only the outermost electrons are drawn: • dots for one atom and × crosses for the other, so you can see where each shared electron came from. Ions are written in square brackets with the charge at the top right; in a covalent bond the circles of the two atoms overlap and the shared pairs sit in the overlap.

Rules used everywhere: octet = 8 outermost electrons (duplet 2 for H, He); metal + non-metal → transfer → ionic; non-metal + non-metal → sharing → covalent; electronegativity difference ≥ 1.7 → ionic, < 1.7 → covalent; criss-cross the valencies (charges) and simplify.

SECTION AAnswer all · 8 × 1 = 8 marks
1.
Which pair of elements is most likely to form an ionic compound? (Use the electronegativity values given.)
(a) carbon and sulphur(b) nitrogen and hydrogen(c) lithium and chlorine(d) phosphorus and chlorine
(1 mark)

💡 Work out all four differences – which one is at least 1.7?

✅ Answer: (c) lithium and chlorine

Differences: C–S 2.58 − 2.55 = 0.03; N–H 3.04 − 2.20 = 0.84; Li–Cl 3.16 − 0.98 = 2.18; P–Cl 3.16 − 2.19 = 0.97. Only Li–Cl is 1.7 or more → ionic (അയോണിക ബന്ധനം). Lithium is a metal and chlorine a non-metal.

Marking: 1 mark for (c).

📖 Review this on Page 8 · The 1.7 rule

2.
An atom that gains electrons becomes a negatively charged ion called .
(1 mark)

💡 Cation or anion – which one is negative?

✅ Answer: anion (ആനയോൺ)

Gaining electrons gives more electrons than protons → a negative ion, an anion. Atoms that lose electrons become positive ions, cations.

Marking: 1 mark.

📖 Review this on Page 4 · Cations and anions

3.
Which of these ions does not have the same electron configuration as neon (2, 8)?
(a) Na+(b) Mg2+(c) F−(d) K+
(1 mark)

💡 Count the electrons left in each ion.

✅ Answer: (d) K+

Na+ (11 − 1 = 10 electrons), Mg2+ (12 − 2 = 10) and F− (9 + 1 = 10) all have 2, 8. K+ has 19 − 1 = 18 electrons: 2, 8, 8 – the configuration of argon.

Marking: 1 mark for (d).

📖 Review this on Page 5 · Ions and their configurations · Page 2 · Charges

4.
Find the relation and fill in:   MgO : ionic bond  ::  H2S :
(1 mark)

💡 Two non-metals …

✅ Answer: covalent bond (സഹസംയോജകബന്ധനം)

Hydrogen and sulphur are both non-metals; the difference is 2.58 − 2.20 = 0.38, less than 1.7 → covalent bond. (MgO: 3.44 − 1.31 = 2.13 → ionic.)

Marking: 1 mark.

📖 Review this on Page 7 · Covalent compounds · Page 8 · Electronegativity

5.
The valency of sulphur (Z = 16) is .
(1 mark)

💡 How many electrons does it need to reach 8?

✅ Answer: 2

Sulphur is 2, 8, 6. It needs 8 − 6 = 2 more electrons for an octet, so its valency (സംയോജകത) is 2.

Marking: 1 mark.

📖 Review this on Page 9 · Valency

6.
Pick the odd one out and give the reason:   KCl,  CaO,  PCl3,  LiF
(1 mark)

💡 Which one has no metal in it?

✅ Answer: PCl3 – the only covalent compound

KCl (3.16 − 0.82 = 2.34), CaO (3.44 − 1.00 = 2.44) and LiF (3.98 − 0.98 = 3.00) are ionic – a metal with a non-metal, difference ≥ 1.7. PCl3 is made of two non-metals: 3.16 − 2.19 = 0.97 < 1.7 → covalent.

Marking: ½ mark for PCl3, ½ mark for the reason.

📖 Review this on Page 8 · Electronegativity table · Page 7 · Ionic vs covalent

7.
The correct formula of calcium nitrate is
(a) CaNO3(b) Ca2NO3(c) Ca(NO3)2(d) Ca2(NO3)3
(1 mark)

💡 The total charge of a salt is zero.

✅ Answer: (c) Ca(NO3)2

Ions: Ca2+ and NO3−. Write Ca NO3, swap the charge numbers → Ca1(NO3)2. Omit the 1 and keep the brackets because the radical is taken twice: Ca(NO3)2. Check: (+2) + 2 × (−1) = 0.

Marking: 1 mark for (c).

📖 Review this on Page 10 · Salts and radicals

8.
Which of the following is a property of covalent compounds?
(a) very high melting points(b) conduct electricity when molten(c) dissolve in organic solvents such as kerosene(d) hard crystalline solids
(1 mark)

💡 Three of the four describe ionic compounds.

✅ Answer: (c) dissolve in organic solvents such as kerosene (ഓർഗാനിക് ലായകങ്ങൾ)

Covalent compounds are generally insoluble in water but soluble in organic solvents (kerosene, carbon tetrachloride, benzene); they have low melting points and do not conduct. The other three are properties of ionic compounds.

Marking: 1 mark for (c).

📖 Review this on Page 7 · Properties of covalent compounds

SECTION BAnswer all · 5 × 2 = 10 marks
9.
Potassium (Z = 19) and sulphur (Z = 16) take part in ionic bonding. (a) Write the equations for the formation of the potassium ion and the sulphide ion from the atoms. (b) Write the electron configurations of the two ions. Which noble gas do both resemble?
(2 marks)

💡 Metal → loses; non-metal → gains.

🎬 Step by step
✅ Answer: (a) K → K+ + 1e−; S + 2e− → S2−   (b) both 2, 8, 8 – like argon

(a) Potassium (2, 8, 8, 1) has 1 outermost electron and gives it away: K → K+ + 1e−. Sulphur (2, 8, 6) needs 2 electrons: S + 2e− → S2−.

(b) K+: 19 − 1 = 18 electrons → 2, 8, 8; S2−: 16 + 2 = 18 electrons → 2, 8, 8. Both have the octet of argon (അഷ്ടകവിന്യാസം). The protons do not change: 19 and 16.

Marking: (a) ½ + ½; (b) configurations ½, argon ½.

📖 Review this on Page 4 · Fig 3.1, 3.2 equations · Page 5 · Mg²⁺ and O²⁻

10.
Hydrogen sulphide (H2S) is the gas that smells of rotten eggs. Draw the electron dot diagram of an H2S molecule (H, Z = 1; S, Z = 16). How many single bonds does it have?
(2 marks)

💡 Draw it like water – sulphur is in the same group as oxygen.

🎬 Step by step
✅ Answer: 2 single bonds: H–S–H

Sulphur (2, 8, 6) has 6 outermost electrons (×) and needs 2; each hydrogen has 1 (•) and needs 1. S shares one pair with each H.

Sulphur now has 8 electrons around it (2 shared pairs + 2 lone pairs) and each hydrogen 2 (duplet). Two single bonds: H–S–H.

Marking: diagram 1½ (shared pairs ½ each, lone pairs ½), number of bonds ½.

📖 Review this on Page 7 · H₂O, Fig 3.11 (same pattern)

11.
Using the electronegativity values, find the nature of the bond in (a) lithium oxide, Li2O (b) sulphur dioxide, SO2. Show the working.
(2 marks)

💡 Always larger − smaller, then compare with 1.7.

🎬 Step by step
✅ Answer: (a) 2.46 → ionic   (b) 0.86 → covalent

(a) Li–O: 3.44 − 0.98 = 2.46. 2.46 ≥ 1.7 → ionic.

(b) S–O: 3.44 − 2.58 = 0.86. 0.86 < 1.7 → covalent (a polar covalent bond; oxygen carries δ−).

Marking: (a) difference ½, type ½; (b) difference ½, type ½.

📖 Review this on Page 8 · Fig 3.12 and the 1.7 rule

12.
Aluminium (Z = 13) combines with sulphur (Z = 16). (a) Find the valency of each element from its electron configuration. (b) Write the formula of the compound by the criss-cross method.
(2 marks)

💡 Al₂O₃ works the same way.

🎬 Step by step
✅ Answer: (a) Al 3, S 2   (b) Al2S3

(a) Al: 2, 8, 3 → gives 3 electrons → valency 3. S: 2, 8, 6 → takes 2 → valency 2.

(b) Write Al S (less electronegative first), swap the valencies as subscripts: Al2S3. 2 and 3 have no common factor → Al2S3 (aluminium sulphide).

Marking: (a) ½ + ½; (b) 1 mark.

📖 Review this on Page 9 · Valency finder · Page 10 · Al₂O₃ step by step

13.
(a) Common salt melts only at about 801 °C. Why do ionic compounds have very high melting points? (b) Naphthalene balls kept in a cupboard slowly become smaller and disappear. Naphthalene is a covalent compound. Which property of covalent compounds does this show?
(2 marks)

💡 Ions attract strongly; molecules attract weakly.

🎬 Step by step
✅ Answer: (a) strong attraction between oppositely charged ions   (b) low melting / boiling points – volatile

(a) An ionic crystal (ക്രിസ്റ്റലുകൾ) is held together by the strong electrostatic force of attraction between oppositely charged ions (Na+ and Cl−) on all sides. A lot of energy is needed to pull them apart, so the melting point (ഉരുകൽനില) is very high.

(b) Covalent compounds generally have low melting and boiling points: the forces between their molecules are weak, so naphthalene slowly turns into vapour at room temperature – it is volatile. (Ionic compounds are non-volatile.)

Marking: (a) 1 mark; (b) 1 mark.

📖 Review this on Page 5 · Properties of ionic compounds, crystal lab · Page 7 · Properties of covalent compounds

SECTION CAnswer all · 4 × 3 = 12 marks
14.
Calcium (Z = 20) and chlorine (Z = 17) form calcium chloride. (a) Write the electron configurations of calcium and chlorine.
(b) Draw the electron dot diagram to show the formation of calcium chloride.
(c) How many electrons and protons are there in the calcium ion? What is its charge?
(3 marks)

💡 One calcium atom has 2 electrons to give; one chlorine needs only 1.

🎬 Step by step
✅ Answer: (a) Ca 2, 8, 8, 2, Cl 2, 8, 7   (b) [Ca]2+ 2[Cl]− → CaCl2   (c) 18 electrons, 20 protons, +2

(a) Ca: 2, 8, 8, 2; Cl: 2, 8, 7.

(b) Calcium gives its 2 outermost electrons (•), one to each of two chlorine atoms (7 × each):

Ca2+ (2, 8, 8) and two Cl− (2, 8, 8) → CaCl2, ionic (3.16 − 1.00 = 2.16).

(c) Calcium ion: 20 − 2 = 18 electrons, 20 protons (unchanged) → charge 20 − 18 = +2.

Marking: (a) ½ + ½; (b) 1 mark (two Cl ½, brackets and charges ½); (c) 1 mark.

📖 Review this on Page 5 · Fig 3.5, Table 3.6 · Page 4 · Dot diagrams

15.
Carbon dioxide (CO2) is a covalent compound (C, Z = 6; O, Z = 8). (a) Draw the electron dot diagram of a CO2 molecule.
(b) How many electron pairs does carbon share with each oxygen atom? Name this type of bond.
(c) Each C–O bond is polar (difference 0.89), yet the CO2 molecule is non-polar. Why?
(3 marks)

💡 Each oxygen needs 2 more – how many pairs per side?

🎬 Step by step
✅ Answer: (b) 2 pairs with each O – double bonds, O=C=O   (c) its shape: the two pulls cancel

(a) C (2, 4) has 4 outermost electrons (•) and needs 4; each O (2, 6) has 6 (×) and needs 2.

(b) Carbon shares 2 pairs with each oxygen → two double bonds (ദ്വിബന്ധനം): O=C=O (4 shared pairs in all). Every atom now has 8.

(c) The molecule is straight (linear, ജ്യാമിതീയ ആകൃതി): the two oxygens pull the shared electrons equally in opposite directions, so the pulls cancel and the molecule as a whole is non-polar.

Marking: (a) 1 mark; (b) 2 pairs ½, double bond ½; (c) 1 mark.

📖 Review this on Page 6 · O₂ double bond, Fig 3.8 · Page 8 · Shape box

16.
Complete the table.
Positive ionNegative ionFormula of the saltName
K+SO42−(i) ……potassium sulphate
Al3+SO42−(ii) ……aluminium sulphate
Mg2+CO32−(iii) ……magnesium carbonate
Al3+PO43−(iv) ……aluminium phosphate
(v) ……CO32−(NH4)2CO3ammonium carbonate
Na+(vi) ……Na3PO4sodium phosphate
(3 marks)

💡 Write the two charge numbers crosswise; divide if you can.

🎬 Step by step
✅ Answer: (i) K2SO4 · (ii) Al2(SO4)3 · (iii) MgCO3 · (iv) AlPO4 · (v) NH4+ · (vi) PO43−
Positive ionNegative ionFormula of the saltName
K+SO42−(i) K2SO4potassium sulphate
Al3+SO42−(ii) Al2(SO4)3aluminium sulphate
Mg2+CO32−(iii) MgCO3magnesium carbonate
Al3+PO43−(iv) AlPO4aluminium phosphate
(v) NH4+CO32−(NH4)2CO3ammonium carbonate
Na+(vi) PO43−Na3PO4sodium phosphate

Positive ion first, swap the charge numbers, simplify by the common factor, omit 1, and put a radical in brackets when it is taken more than once. Check: the total charge is zero – e.g. Al2(SO4)3: 2 × (+3) + 3 × (−2) = 0; MgCO3: Mg2(CO3)2 ÷ 2.

Marking: ½ mark for each blank.

📖 Review this on Page 10 · Salt table, criss-cross machine

17.
(a) From H2O, Cl2, NH3, CO2 and HCl, pick out the polar molecules.
(b) Find the electronegativity difference of the N–H bond. Draw the bond showing the partial charges δ+ and δ−.
(c) Ammonia molecules are held to one another and to water molecules by hydrogen bonds. What is hydrogen bonding?
(3 marks)

💡 Same atoms → non-polar. Symmetric shape → non-polar.

🎬 Step by step
✅ Answer: (a) H₂O, NH₃, HCl   (b) 0.84; δ+H–Nδ−   (c) δ+ H (bonded to F, O or N) attracted by an electronegative atom

(a) Polar (പോളാർ തന്മാത്രകൾ): H2O, NH3, HCl. Cl2 has two identical atoms (equal pull); CO2 has polar bonds but its shape cancels them.

(b) 3.04 − 2.20 = 0.84 → polar covalent. Nitrogen attracts the shared pair more: δ+H–Nδ−.

(c) Hydrogen bonding (ഹൈഡ്രജൻ ബന്ധനം): when hydrogen is covalently bonded to a highly electronegative atom (F, O or N), it gets a δ+ charge and is attracted by an electronegative atom of the same or another molecule. It is an intermolecular force (അന്തർതന്മാത്രാബലങ്ങൾ).

Marking: 1 mark each part ((a) all three ½, none wrong ½; (b) difference ½, δ ½).

📖 Review this on Page 8 · Polar nature, hydrogen bonding box

SECTION DAnswer all · 2 × 5 = 10 marks
18.
The atomic numbers of five elements are given. The letters are not their real symbols:   A = 3,  D = 7,  E = 9,  G = 18,  J = 20. Electronegativity: A 0.98, D 3.04, E 3.98.
(a) Write the electron configurations of all five. Which of them does not usually form compounds? Why?
(b) Which element forms a positive ion by losing two electrons? Write the equation.
(c) Write the formula of the compound formed by J and D.
(d) Draw the electron dot diagram for the formation of the compound of A and E. What type of bond is formed?
(e) Find the nature of the bond in DE3. Which atom carries the partial negative charge?
(5 marks)

💡 Write the five configurations first – everything follows from them.

🎬 Step by step
✅ Answer: (a) G – octet   (b) J → J2+ + 2e−   (c) J3D2   (d) [A]+[E]−, ionic   (e) covalent; E is δ−

(a) A 2, 1; D 2, 5; E 2, 7; G 2, 8, 8; J 2, 8, 8, 2. G already has 8 electrons in its outermost shell (octet) – it is stable, a noble gas, and does not usually react.

(b) J (2, 8, 8, 2) loses its 2 outermost electrons: J → J2+ + 2e− (J2+ 2, 8, 8).

(c) Valency of J = 2 (gives 2); D (2, 5) takes 3 → valency 3. Criss-cross: J3D2.

(d) A gives its one electron to E: A+ (2, like helium) and E− (2, 8). Difference 3.98 − 0.98 = 3.00 ≥ 1.7 → ionic bond; formula AE.

(e) 3.98 − 3.04 = 0.94 < 1.7 → covalent (polar). E, the more electronegative atom, carries δ−; D carries δ+.

Real elements: A Li, D N, E F, G Ar, J Ca – J3D2 is calcium nitride, AE lithium fluoride, DE3 nitrogen trifluoride.

Marking: 1 mark for each part (½ + ½ where there are two answers).

📖 Review this on Page 3 · Octet checker · Page 9 · Valency · Page 4 · Dot diagrams · Page 8 · δ+ and δ−

19.
Read the passage and answer the questions.
During the monsoon, the health worker at a primary health centre in Alappuzha shows how to make ORS (ഒ.ആർ.എസ്. – oral rehydration solution): one packet, containing common salt (sodium chloride), glucose and potassium chloride, is dissolved in one litre of boiled and cooled water. At the school science club, Anu dips the two electrodes of a simple circuit (two torch cells and a small bulb) into the ORS solution, a glucose solution and coconut oil, and then presses them against dry crystals of common salt. Only the ORS solution lights the bulb. At home her mother removes a grease stain from a shirt with a little kerosene.
(a) Why does the ORS solution conduct electricity but the dry salt crystals do not?
(b) Potassium (Z = 19) and chlorine (Z = 17) form potassium chloride. Write the equations for the formation of its ions.
(c) Using the electronegativity values, show that potassium chloride is ionic and that the C–H bonds in glucose are covalent. Why does the glucose solution not light the bulb?
(d) Common salt dissolves in water but not in coconut oil, while grease dissolves in kerosene. Explain.
(e) Water is called the universal solvent. Which feature of the water molecule helps it to dissolve salt? Draw a water molecule showing δ+ and δ−.
(5 marks)

💡 Ions that can move → current. No ions → no current.

🎬 Step by step
✅ Answer: (a) free-moving ions in solution   (b) K → K+ + 1e−; Cl + 1e− → Cl−   (c) 2.34 ionic, 0.35 covalent – no ions   (d) ionic → polar solvents, covalent → organic solvents   (e) water is polar

(a) Salt is ionic. In the solution its ions (Na+, Cl−, K+) are free to move and carry the current. In the dry crystal the ions are held fixed in place – ionic compounds conduct only when molten or dissolved.

(b) K → K+ + 1e− (2, 8, 8, 1 → 2, 8, 8); Cl + 1e− → Cl− (2, 8, 7 → 2, 8, 8); K+ + Cl− → KCl.

(c) K–Cl: 3.16 − 0.82 = 2.34 ≥ 1.7 → ionic. C–H: 2.55 − 2.20 = 0.35 < 1.7 → covalent. Glucose is a covalent compound; it dissolves as whole molecules and forms no ions, so there is nothing to carry the current.

(d) Ionic compounds are generally soluble in polar solvents (പോളാർ ലായകങ്ങൾ) like water, not in oils. Grease is a covalent substance; covalent compounds dissolve in organic solvents such as kerosene (മണ്ണെണ്ണ) but not in water.

(e) Water is a polar molecule: O (3.44) pulls the shared pairs from H (2.20), so O is δ− and each H is δ+. The δ− oxygen attracts Na+ and the δ+ hydrogens attract Cl−, pulling the ions out of the crystal. (Hydrogen bonding between water molecules also explains its other special properties.)

Marking: 1 mark for each part (½ + ½ where there are two answers).

📖 Review this on Page 5 · Properties of ionic compounds · Page 12 · Conductivity lab · Page 8 · Water and hydrogen bonds · Page 13 · Applications

Marks summary

SectionQuestionsMarks eachTotalTopics
A1–8181.7 rule, anion, ions like neon, ionic : covalent, valency of S, odd one out, Ca(NO₃)₂, covalent properties
B9–13210ion formation equations (K, S), dot diagram of H₂S, bond type of Li₂O and SO₂, Al₂S₃ by criss-cross, melting points and volatility
C14–17312formation of CaCl₂, dot diagram and shape of CO₂, salts with radicals, polarity and hydrogen bonding
D18–19510five elements with letters, Kerala case study on ORS and conductivity
Total40
⏱️ Time management (15 min cool-off + 90 minutes)
🎉 Finished the chapter?

Count your marks: 32 or more – excellent; 24–31 – good, revise the pages linked under the questions you missed; below 24 – go back through pages 3 to 10 with their labs and do the scored quiz again. Then return to the chapter home and tick off what you have learned.